Question

I need help with this Geometry HWI need to find the surface area

Answer 1

the surface are is the sum of all areas of the pyramid

so

Lateral triangle

the area is

`\begin{gathered} A=(b* h)/(2) \\ \\ A=(4*11.1)/(2) \\ \\ A=22.2 \end{gathered}`

This triangle is repeated 3 times since it makes all the faces except the lower one

Low triangle

`\begin{gathered} A=(b* h)/(2) \\ \\ A=(4*3.5)/(2) \\ \\ A=7 \end{gathered}`

Total surface Area

we add each area of ​​each face of the pyramid

so

`\begin{gathered} A=22.2+22.2+22.2+7 \\ A=73.6 \end{gathered}`

Then the surface Are is 73.6 square meters