The question is to show that the probability that each of the four players in a game of bridge receives one ace is=
= (24⋅48!⋅13^4)/52!
My explanation so far is that there are 4! ways to arrange the 4 aces, 48! ways to arrange the other cards, and since each arrangement is equally likely we divide by 52!. I believe the 13^4 represents the number of arrangements to distribute 4 aces among 13 cards.