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When randomly choosing two cards from a standard deck of card without replacement, what is the probability of choosing a face and then an ace ?

User IoT User
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Total number of cards: 52
Number of faces: 4 J + 4 Q + 4 k = 12
Number of aces: 4.

Combined probability of choosing a face and then an ace:

[12/52] * [4/51] = 48/[52*51] = 0.018
User Umakant
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