How much thermal energy (q) is required to heat 15.2g of a metal (specific heat=0.397J/C) from 21.0C to 40.3C? Show steps please.

Question

asked Aug 17, 2017 29.1k views

1 Answer

Patrick Kwinten · Answer 1 · 2017-08-24T11:28:22+0000

Q = ?

Cp = 0.397 J/ºC

Δt = 40.3 - 21.0 => 19.3 ºC

m = 15.2 g

Q = m x Cp x Δt

Q = 15.2 x 0.397 x 19.3

Q ≈ 116.46 J

hope this helps!