Question

Solve for y. ln(y-1)-ln2=x+ln x

Answer 1

`ln(y - 1) - ln(2) = x + ln(x)`

`e^(ln(y - 1) - ln(2)) = e^(x + ln(x))`

`(e^(ln(y - 1)))/(e^(ln(2))) = e^(x) * e^(ln(x))`

`(y - 1)/(2) = e^(x) * x`

`(1)/(2)y - (1)/(2) = xe^(x)`

`2((1)/(2)y - (1)/(2)) = 2xe^(x)`

`y - 1 = 2xe^(x)`

`y = 2xe^(x) + 1`