Question

Pls help pls help help pls

Answer 1

Approximate maximum height is 5 ft

`h((18)/(32) )= 5 \ ft`

Explanation:

`h(t)=-16t^(2) + 18t` ---------- (1)

Differentiate equation (1) w.r.t t and equate it to zero (in order to determine maxima)

`h^(')(t) = -32t+18`

`0= -32t+18`

`t=(18)/(32)`

Substitute this value in equation (1)

`h((18)/(32) )=-16((18)/(32) )^(2) + 18((18)/(32) )`

`h((18)/(32) )=-5+ 10`

`h((18)/(32) )= 5 \ ft`