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Evaluate the integral: integral of t sinh mt dt

1 Answer

6 votes
integrate by parts

f = t, df = dt,
dg = sinh(mt)dt
g = cosh(mt)/m

put them together

tcosh(mt)/m - /m * ∫cosh(mt)dt

u = mt, du = mdt
tcosh(mt)/m - /m^2 * ∫cosh(u)dt
integral of cosh(u) = sinh(u)

tcosh(mt)/m - sinh(u)/m^2 + c1

substitute back in the u (mt)
tcosh(mt)/m - sinh(mt)/m^2 + c1

You can simplify this

((mt*cosh(mt)-sinh(mt)))/m^2
User Goyalankit
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