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7 votes
7 votes
A = 8, b = 24, c = 18

User Qumber
by
3.1k points

1 Answer

13 votes
13 votes

The sides of the triangle are

a=18

b=24

c=10.3

Let the angles be A, B and C

Then,


\begin{gathered} \cos A=(b^2+c^2-a^2)/(2bc) \\ =43.59^o \end{gathered}

User Bob Black
by
2.9k points
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