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Find the second derivative y= x^2lnx
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Apr 27, 2017
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Find the second derivative y= x^2lnx
Mathematics
high-school
Divyesh Pal
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Divyesh Pal
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first we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Thorsten Scherf
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May 3, 2017
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Thorsten Scherf
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