Question

Describe, in detail, how to make 3.0 liters of a 3.5 molar HCl solution from an 18.5 molar HCl stock solution

Answer 1

Take 0.57 L of 18.5 M HCl solution and make its volume upto 3 L by adding it 2.43 L of water.

Step-by-step explanation:

`M_1V_1=M_2V_2` (Dilution)

where,

`M_1\text{ and }V_1` are the , molarity and volume of acid which is formed after dilution

`,M_2\text{ and }V_2` are the , molarity and volume of acid which is diluted

We are given:

`M_1=3.5 M\\V_1=3.0 L\\M_2=18.5 M\\V_2=?`

Putting values in above equation, we get:

`3.5 M* 3.0 L=18.5 M* V_2\\\\V_2=0.57 L`

Volume of 18.5 M HCl required = 0.57 L

Volume to be added in 0.57 L of 18.5 M HCl so that we have 3.5 M of HCl solution:

`V_1-V_2=3.0 L - 0.57 L = 2.43 L`

Take 0.57 L of 18.5 M HCl solution and make its volume upto 3 L by adding it 2.43 L of water.

Answer 2

C1V1=C2V2,
where C is concentration and V is volume,
so let say C1=18.5M, V1=?,
C2=3.5M, V2=3.0L,
now solve for V1, in this case V1=0.57L, so in order to make a 3.0L solution we will need to take 0.57L of stock HCl and add 2.43L of water.