Question

How many hydrogen atoms are present in 2.00mg of aspartame

Answer 1

2.167*10^22 atoms of hydrogen

Answer 2

`7.37* 10^(19)` number of H atoms are present in 2.00 mg of aspartame

Step-by-step explanation:

Molecular formula of aspartame is
`C_(14)H_(18)N_(2)O_(5)`

So, 1 molecule of aspartame contains 18 atoms of H

Molar mass of aspartame = 294.307 g/mol

Number of moles = (mass)/(molar mass)

So, 2.00 mg of aspartame =
`(2.00* 10^(-3))/(294.307)` moles of aspartame

We know, 1 mol of a particle =
`6.023* 10^(23)` number of particle

So, number of molecules of aspartame in
`(2.00* 10^(-3))/(294.307)` moles of aspartame =
`(2.00* 10^(-3))/(294.307)* 6.023* 10^(23)`

So number of H atoms in
`(2.00* 10^(-3))/(294.307)` moles of aspartame =
`(2.00* 10^(-3))/(294.307)* 6.023* 10^(23)* 18` =
`7.37* 10^(19)`