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7) Calculate the pressure exerted by 89.10 grams of hydrogen gas in a 8,583. mL sealed flask at 140.0oC.Pressure = _______ atm

User Logworthy
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To solve this problem, we need to know a few things first:

We can solve it using the following formula: PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

We also know that n = m/MM

where:

m = mass

MM = molar mass

Step 1 - Let's find out the number of moles of the hydrogen gas

Step 2 - Transform all units into the unit of the gas constant R (0.082 atm.L/K.mol

Step 3 - use the formula PV = nRT to find out the pressure

Step 1:

MM of H2 = 1x2 = 2 g/mol

m = 89.10

n = 89.10/2

n = 44.55 moles

Step 2:

1000 mL = 1L

8,583 mL = 8.583 L

TK = Tc + 273.15

TK = 140 + 273.15

Tk = 413.15

Step 3:

PV = nRT

P x 8.583 = 44.55 x 0.082 x 413.15

P = 1,509.7/8.585

P = 175.8 atm

Answer: The answer is 175.8 atm

User Artin Falahi
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