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PLEASE HELP I DON'T KNOW HOW TO SOLVE THIS.

PLEASE HELP I DON'T KNOW HOW TO SOLVE THIS.-example-1
User Rtdp
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3 Answers

8 votes

Explanation

  • Find the domain.

To find the domain from the graph, you have to focus only x-axis because domain is the set of x-value.

From the graph, we can see that domain starts at x = 0 and keeps going and going positive infinitely. That means the domain must be greater or equal to 0.

Here is an easier way to understand


\large \boxed{ \sf{left/start}} \Longrightarrow \large \boxed{ \sf{right/end}}


\large \sf{left = 0} \\ \large \sf{right = + \infin}

And if we combine both, we get


0 \leqslant x \leqslant + \infin

But we don't usually write positive infinity, therefore we convert to


0 \leqslant x \longrightarrow x \geqslant 0 \\ x \geqslant 0

Answer


x \geqslant 0

If you have any questions related to this answer, feel free to ask in comment.

User CarpeNoctumDC
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4.9k points
6 votes

Answer: b

Explanation:

X is defined for all numbers on the domain starting at x=0. It doesn’t show or mention a cutoff/equation in the picture so it’s safe to assume it continues forever

User Jreikes
by
4.0k points
10 votes

Explanation

  • Find the domain.

To find the domain from the graph, you have to focus only x-axis because domain is the set of x-value.

From the graph, we can see that domain starts at x = 0 and keeps going and going positive infinitely. That means the domain must be greater or equal to 0.

Here is an easier way to understand


\large \boxed{ \sf{left/start}} \Longrightarrow \large \boxed{ \sf{right/end}}


\large \sf{left = 0} \\ \large \sf{right = + \infin}

And if we combine both, we get


0 \leqslant x \leqslant + \infin

But we don't usually write positive infinity, therefore we convert to


0 \leqslant x \longrightarrow x \geqslant 0 \\ x \geqslant 0

Answer


x \geqslant 0

If you have any questions related to this answer, feel free to ask in comment.

User Rushik
by
4.1k points