131k views
2 votes
The sum of two-thirds of a number and one-fourth of the number exceeds five-sixths of that number by two. . . Which equation could be used to determine the number?. A) 2/3 +1/4 n = 5/6n + 2. B) 2/3n + 1/4 = 5/6n + 2. C) 2/3n + 1/4n = 5/6n + 2

User Reticent
by
7.1k points

2 Answers

0 votes
Answer:
C ) 2/3 n + 1/4 n = 5/6 n + 2
Thank you.
User Piotr Owsiak
by
8.0k points
5 votes

Answer:

C)
(2)/(3) n + (1)/(4) n = (5)/(6) n + 2


Step-by-step explanation:

Assume that the number is n


For the left hand side:

Two thirds of the number is
(2)/(3) n

one fourth of the number is
(1)/(4) n

The sum means that we will add them

Therefore, the left hand-side is:


(2)/(3) n +
(1)/(4) n


For the right hand side:

five sixth of the number is
(5)/(6) n

two is 2

exceeds means that we will add

Therefore,the right-hand side is:


(5)/(6) n + 2


Combining the two sides, we will get the expression:


(2)/(3) n + (1)/(4) n = (5)/(6) n + 2


Hope this helps :)

User Spassvogel
by
7.6k points