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If the ordinate is three more than twice the abscissa and x ∈ {-1, 0, -1/3}, which of the following sets of ordered pairs satisfies the given conditions?. A) {(-1, 1), (0, 3), (-1/3, 7/3)}. B) {(-1, 1), (0, 3), (-1/3, 11/3)}. C) {(-1, -1), (0, 3), (-1/3, 1)}

User Mgag
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1 Answer

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y = 2 x + 3
We will plug in the numbers from the sets:
1 = 2 · ( -1 ) + 3 = - 2 + 3= 1 ( correct )
3 = 2 · 0 + 3 = 0 + 3= 3 ( correct )
7/3 = 2 · (-1/3 ) + 3 = -2/3 + 3 = - 2/3 + 9 /3 = 7/3 ( correct )
Answer : A ) { (-1, 1 ), ( 0, 3 ) , ( -1/3, 7/3 ) }
User Abdusco
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