Question

A uniform conducting rod of length 34 cm has a potential difference across its ends equal to 39 mV (millivolts). What is the magnitude of the electric field inside the conductor in units of N/C?

Answer 1

Electric field, E = 0.114 N/C

Step-by-step explanation:

Given that,

Length of the conducting rod, l = 34 cm = 0.34 m

The potential difference across the ends of the rod,
`V=39\ mV=39* 10^(-3)\ V`

Let E is the magnitude of electric field inside the conductor. It can be calculated as :

`E=(V)/(d)`

`E=(39* 10^(-3))/(0.34)`

E = 0.114 N/C

So, the magnitude of the electric field inside the conductor is 0.114 N/C. Hence, this is the required solution.