A 2kg ball rolls down the hill. By the time it is at the bottom the balls kinetic energy is 25 J. What is the velocity at the bottom of the hill

Question

asked Aug 26, 2022 129k views

1 Answer

ThunderWiring · Answer 1 · 2022-08-31T03:41:14+0000

Calculate the velocity(v) at the bottom of hill.

As we know ,

$\bf\: Kinetic \: energy = (1)/(2) * m * {v}^(2)$

$\red \bigstar \bf \: putting \: the \: values$

$\rightarrow \: 25 = (1)/(2) * 2 * {v}^(2)$

$\rightarrow \: 25 * 2 = 1 * 2 * {v}^(2)$

$\rightarrow \: 50 = 2 * {v}^(2)$

$\rightarrow \: {v}^(2) = \cancel (50)/(2)$

$\rightarrow \: {v}^(2) = 25$

$\rightarrow \: v = √(25)$

$\rightarrow \: v = 5 \: m {s}^( - 1)$