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Point X is located at (2, −6), and point Z is located at (0, 5). Find the y value for the point Y that is located one over five the distance from point X to point Z.

User Stiffo
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Final answer:

The y-value for point Y, one fifth of the distance from X to Z, is calculated by adding 1/5 of the difference between Z's and X's y-values to X's y-value, resulting in -3.8.

Step-by-step explanation:

To find the y-value for the point Y that is located one over five the distance from point X to point Z, a simple way of thinking about this problem is to consider it as finding 1/5 of the way along a line segment from point X to point Z. First, we find the difference in y-values between point Z and point X, then we multiply that difference by 1/5 to find how much the y-value changes when moving from X towards Z.

Z's y-value is 5, and X's y-value is -6. So the difference is 5 - (-6) = 11. Now, 1/5 of this distance is 11 * 1/5 = 2.2. Since we must start at point X and move towards Z, we add this fraction of the distance 2.2 to the y-value at X.

The calculation looks like this: -6 + 2.2 = -3.8. Therefore, the y-value for point Y, which is one fifth of the distance from X to Z, is -3.8.

User Natalia
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I think is (7,-5) Because 1/5 is just like rise/run  from point X one up, and 5 to the right side.
User DonL
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