Solve for T in a/2=ae^-9.548t

asked Jun 26, 2017 74.9k views

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$(a)/(2)=ae^(-9.548t)\\ (1)/(2)=e^(-9.548t)\\ -9.548t=\ln (1)/(2)\\ t=-(\ln(1)/(2))/(9.548)\\ t=(\ln 2)/(9.548)$

Aniello answered Jul 1, 2017

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