Question

The sum of two positive numbers is 55 times their difference. What is the ratio of the larger number to the smaller number?

Answer 1

`x;y\in\mathbb{R^+}-two\ positive\ numbers\ (x \ \textgreater \ 0\ and\ y \ \textgreater \ 0)\\x \ \textgreater \ y\\\\x+y=55(x-y)\\\\x+y=55x-55y\ \ \ \ |subtract\`

Answer 2

Hello,

Let's assume
a the largest number
b the smallest. not equal 0

a+b=55(a-b)
==>a/b+1=55a/b-55
==>a/b-55a/b=-56
==>-54 a/b=-56
==>a/b=56/54
==>a/b=28/27