Question

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds)

5.50 × 10-11 Hz
2.39 × 10-50 Hz
5.45 × 1018 Hz
1.633 × 1027 Hz

Answer 1

Option (3)

Step-by-step explanation:

The formula to find the energy of each photon is given by

E = h f

Where, h is the Plank's constant and f be the frequency.

`3.611*  10^(-15) = 6.626 * 10^(-34) *  f`

f =
`5.45 *  10^(18)` Hz

Answer 2

The answer is 5.45 x 1018 Hz. Good luck!