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An object moving at a velocity of 32 m/s slows to a stop in 4 seconds. What was its acceleration?v = vo + at

User BlueMoon
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1 Answer

23 votes
23 votes

ANSWER


-8m/s^2

Step-by-step explanation

Parameters given:

Initial velocity, v0 = 32 m/s

Final velocity, v = 0 m/s

Time, t = 4 seconds

To find the acceleration, apply the formula for acceleration:


a=(v-v0)/(t)

Therefore, we have that:


\begin{gathered} a=(0-32)/(4) \\ a=(-32)/(4) \\ a=-8m/s^2 \end{gathered}

That is its acceleration.

User Vitani
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