Question

An object moving at a velocity of 32 m/s slows to a stop in 4 seconds. What was its acceleration?v = vo + at

Answer 1

`-8m/s^2`

Step-by-step explanation

Parameters given:

Initial velocity, v0 = 32 m/s

Final velocity, v = 0 m/s

Time, t = 4 seconds

To find the acceleration, apply the formula for acceleration:

`a=(v-v0)/(t)`

Therefore, we have that:

`\begin{gathered} a=(0-32)/(4) \\ a=(-32)/(4) \\ a=-8m/s^2 \end{gathered}`

That is its acceleration.