Question

How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest
to 51 m/s?

Answer 1

t = 16.5s

Step-by-step explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity = 0m/s

Final velocity = 51m/s

Unknown:

Time taken = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

Acceleration =
`(v - u )/(t)`

v is the final velocity

u is the initial velocity

t is the time taken

So;

3.1 =
`(51 - 0)/(t)`

3.1t = 51

t = 16.5s