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Use the matrix tool to solve the system of equations. Choose the correct ordered pair.3x - 8y = -1 -2x + 6y = 1 A.(1, 1/2) B.(1/2, 3) C.(1/2, 1) D.(3,1/2)

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\left\{\begin{array}{ccc}3x-8y=-1\\-2x+6y=1\end{array}\right\\\begin{array}{ccc}(i)\\(ii)\end{array}\left[\begin{array}{ccc}3&-8\\-2&6\end{array}\right\left|\begin{array}{ccc}-1\\1\end{array}\right]\xrightarrow{(i):3}\left[\begin{array}{ccc}1&-(8)/(3)\\-2&6\end{array}\right\left|\begin{array}{ccc}-(1)/(3)\\1\end{array}\right]\xrightarrow{(ii)+2(i)}

\left[\begin{array}{ccc}1&-(8)/(3)\\0&(2)/(3)\end{array}\right\left|\begin{array}{ccc}-(1)/(3)\\(1)/(3)\end{array}\right]\xrightarrow{(ii)\cdot(3)/(2)}\\\left[\begin{array}{ccc}1&-(8)/(3)\\0&1\end{array}\right\left|\begin{array}{ccc}-(1)/(3)\\(1)/(2)\end{array}\right]\xrightarrow{(i)+(ii)\cdot(8)/(3)}\\\left[\begin{array}{ccc}1&0\\0&1\end{array}\right\left|\begin{array}{ccc}1\\(1)/(2)\end{array}\right]


Answer:\boxed{ \left \{ {{x=1} \atop {y=(1)/(2)}} \right.\to\fbox{A.}}
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