Question

Can you please solve this I don't understand perpendicular lines

Answer 1

The equation of the perpendicular line 't' is 3x+y =0

Point slope form y = mx +C

y = - 3x

Explanation:

Step(i):-

Given equation s =
`(1)/(3)x +10` and given point (1,-3)

The equation of the perpendicular line

`y =(x+30)/(3)`

⇒ 3 y = x+30

⇒ x - 3y +30 =0

Step(ii):-

The perpendicular line of the given straight line 's'

b x -ay +k=0

⇒ -3x -y +k=0

This line is passing through the point (1,-3)

-3(1)-(-3)+k=0

k =0

The equation of the perpendicular line -3x-y =0

Final answer:-

The equation of the perpendicular line 3x+y =0

Point slope form y = mx +C

y = - 3x