Question

using the given quadratic function f(x)=x^2+2x-15, find the following information: find the coordinates of the vertex as an ordered pair

Answer 1

f(x) = x² + 2x - 15

The x-coordinate of the vertex is computed as follows:

`\begin{gathered} x_V=(-b)/(2a) \\ x_V=(-2)/(2(1)) \\ x_V=(-2)/(2) \\ x_V=-1 \end{gathered}`

To find the y-coordinate, you need to replace the x-coordinate into the formula, as follows:

`\begin{gathered} y_V=x^2_v+2x_V-15 \\ y_V=(-1)^2_{}+2(-1)_{}-15 \\ y_V=1-2_{}-15 \\ y_V=-16 \end{gathered}`

Then, the vertex is at (-1, -16)