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Consider the balanced reaction bellow. How many moles of barium hydroxide,Ba(OH)2, would be required to react with 117g hydrogen bromide,2HBr+Ba(OH)2=BaBr2+2H2
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Consider the balanced reaction bellow. How many moles of barium hydroxide,Ba(OH)2, would be required to react with 117g hydrogen bromide,2HBr+Ba(OH)2=BaBr2+2H2

User Zeronone
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Mol of HBr = mass/Mr = 117/(1+80) = 1.444 From equation, 2 moles hydrogen bromide reacts with 1 mole of barium hydroxide.... So 1.444 moles of hydrogen bromide react with (1.444/2) = 0.722 moles of barium hydroxide.
User Stonemetal
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