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If a ball is dropped and takes 6.5 seconds to hit the ground below. How far did it fall? Remember in free fall g= -9.8 m/s/s. What is this question asking you to solve for? What variables are being used?

User Ohadinho
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Answer:

See the answers below.

Step-by-step explanation:

To solve this problem we must use the following equation of kinematics.


y=y_(o)+v_(o)*t+(1)/(2)*g*t^(2) \\

where:

y - yo = Fall distance [m]

Vo = initial velocity = 0 (dropped)

t = time = 6.5 [s]

g = gravity acceleration = 9.8 [m/s²]

Now replacing:


y-y_(o)=0 +(1)/(2) *9.8*6.5^(2)\\y-y_(o)=207 [m]

The question is related to the distance between the points where the ball was dropped and the ground.

The variables used are gravitational acceleration, time, fall distance, initial velocity.

User CatBusStop
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