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All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a green followed by a red assuming that the first candy drawn is put back into
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All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues,  What is the probability that a random drawing yields a green followed by a red assuming that the first candy drawn is put back into the packet? 

User Katya Pavlenko
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2 Answers

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Multiply 7(reds) by 4 (greens) to get 2/13
User Gruff Bunny
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probability of drawing a green = 4/13
Probability of drawing a red = 2/13
probability of drawing a green and then a red is 4/13 * 2/13 = 6/169
User ReynierPM
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