Question

In the reaction below, 27.0 8 of acetylene reacted completely with oxygen. Determine how many grams of O2 reacted. Show all your work2C2H2(s) + 502(s) -> 4CO2(g) + 2H2O(8)(acetylene)EditFormatTable12ptParagraphB7AT|||

Answer 1

82.95g of oxygen gas react with 27.0g of acetylene.

Step-by-step explanation:

1st) It is necessary to balance the chemical reaction:

`2C_2H_2+5O_2\rightarrow4CO_2+2H_2O`

With the chemical reaction we know that 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2 and 2 moles of water.

2nd) With the molar mass of acetylene and oxygen we can convert the moles to grams:

- Acetylene molar mass (C2H2): 26.04g/mol

- Oxygen molar mass (O2): 32g/mol

- Conversion of C2H2 moles to grams:

`2moles*(26.04g)/(1mol)=52.08g`

- Conversion of O2 moles to grams:

`5moles*(32g)/(1mol)=160g`

Now we know that 52.08g of acetylene react with 160g of oxygen gas.

3rd) Calculate the grams of oxygen that react with 27.0g of acetylene, using a mathematical rule of three:

`\begin{gathered} 52.08g\text{ C}_2\text{ H}_2-160g\text{ O}_2 \\ 27.0g\text{ C}_2\text{ H}_2-x=\frac{27.0g\text{ C}_2\text{ H}_2*160g\text{ O}_2}{52.08g\text{ C}_2\text{ H}_2} \\ x=82.95g\text{ O}_2 \\ \end{gathered}`

So, 82.95g of oxygen gas react with 27.0g of acetylene.