Question

Two numbers,which differ by3,have a product of88.find the two numbers.

Answer 1

11 and 8

Explanation:

x-y=3

(X)(y)=88

Answer 2

8 and 11, or -8 and -11

Explanation:

Let the bigger number be x and the smaller number be y.

Since they differ by 3, then
`y+3=x`

Since the product is 88, then
`x*y=88`

Substitute
`x=y+3` into the second equation of
`x*y=88` to get:

`(y+3)*y=88`

Multiply accordingly:

`y^2+3y=88`

Subtract 88 from both sides to get a quadratic equation:

`y^2+3y-88=0`

Factor:

`(y-8)(y+11)=0`

`y=8` or
`y=-11`.

There can be two values for y.
If y is 8, then x would be 11 as
`8+3=11`

If y is -11, then x would be -8 as
`-11+3=-8`

The two numbers are 8 and 11, or -8 and -11.