Question

If cot x = .42 and sin x = .92, what is cos x?

Answer 1

`\cot\alpha=(\cos\alpha)/(\sin\alpha)\\\\\cot x=0.42;\ \sin x=0.92;\ \cos x=?\\\\subtitute\\\\(\cos x)/(0.92)=0.42\ \ \ |multiply\ both\ sides\ by\ 0.92\\\\\boxed{\cos x=0.3864\approx0.39}`

Answer 2

`\cot x=(\cos x)/(\sin x)\\ \cos x=\cot x \sin x\\ \cos x=0.42\cdot0.92=0.3864`