Question

What is the solution set of x^2+y^2=26 and x-y=6

Answer 1

Solution is in the picure

Good luck :)

Answer 2

`image`+
`y^(2)`=26

`y^(2) +12x+36+ y^(2) =36`
=
`2y^(2) +12x+36-26=0`
=
`2y^(2) +12x+10=0`
Product = 12
Sum= 10
factoring;
2
`y^(2)`+2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1