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If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s t)(-7)? A. -439 B. -141 C. 153 D. 443

2 Answers

3 votes

Answer:

Option (a) is correct.


s(t(x))=-439

Explanation:

Given :
s(x) = 2- x^2 and
t(x) = 3x

We have to find the value of (s t)(-7) and choose the correct option from the given options.

Consider the given function
s(x) = 2- x^2 and
t(x) = 3x

and we have to find the value of (s t)(x) at x = -7

We first find the value of (st)(x) that is s(t(x))

Thus,
s(t(x))=2-(3x)^2

Simplify,


s(t(x))=2-9x^2

We get, For x = -7 , we have,


s(t(-7))=2-9(-7)^2

Simplify, we have,


s(t(-7))=2-441=-439

Thus,
s(t(x))=-439

User Yixing Liu
by
8.4k points
3 votes
Answer: Option A -439

(s o t)(x)=s(t(x))
(s o t)(-7)=s(t(-7))
x=-7→t(-7)=3(-7)→t(-7)=-21
(s o t)(-7)=s(t(-7))=s(-21)
x=-21→s(-21)=2-(-21)^2=2-441→s(-21)=-439
(s o t)(-7)=s(t(-7))=s(-21)=-439
Answer: Option A -439
User Tamir Daniely
by
8.7k points

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