Question

2H2O2(aq) --> O2(g) + 2H2O(l). If you use 0.20 M of KI instead of 0.10 M of KI, How would this affect: (a)the slopes of your curves, (b) the rates of the reactions, and (c) the numerical value of k for the reaction?

Answer 1

Increasing the concentration of KI will increase the overall rate of the reaction, but it will not affect the slopes of the reaction curves or the numerical value of the rate constant (k).

Step-by-step explanation:

When using a higher concentration of KI (0.20 M instead of 0.10 M) in the reaction, it will not affect the slopes of the curves in a reaction. The slopes of the curves indicate the rate of reaction, and changing the concentration of one of the reactants does not affect the rate at which the reaction occurs.

However, increasing the concentration of KI will increase the overall rate of the reaction. This is because the rate of a chemical reaction is directly proportional to the concentration of the reactants. Therefore, a higher concentration of KI will result in a faster reaction.

The numerical value of the rate constant (k) for the reaction will not change when the concentration of KI is increased. The rate constant is a constant value specific to a particular reaction at a given temperature, and it is not affected by the concentrations of the reactants.

Answer 2

This very much depends on order in respect to KI

order of Zero, no change, order 1, rate doubles, order 2, rate quadruples. Which is also one way of working out the rate order.

no change onto steeper on curves. (0 thro..)

k shouldn't change.

Best Answer is (c) the numerical value of k for the reaction