Question

A rugby player passes the ball 7.00 m across the field, where it is caught at the same height as it left his hand. If the pass was thrown with a 14.2 degree angle, with an initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used, how long did this pass take in seconds?

Answer 1

This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle: Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s So now you should use Vx the same way it is used in a uniform linear movement. d=v*t dx=vx*t t=dx/vx=7m/(11.6m/s)=0.603s