Question

How many grams of water would there be in 100.0g of hydrate? How many moles?

Mass of the hydrate 0.946g
Mass of the anhydrous CuSO4 0.614gCuSO4
Mass of water driven off? 0.347g H2O
The percent water in the hydrate 36.0%

Answer 1

Answer: The mass of water present in given amount of hydrate is 36.68 grams and number of moles of water are 2.04 moles.

Step-by-step explanation:

We are given:

Mass of hydrate = 0.946 grams

Mass of water present = 0.347 grams

We need to calculate the mass of water present in 100 grams of hydrate. By using unitary method, we get:

In 0.946 g of hydrate, the amount of water present is 0.347 g

So, in 100 g of hydrate, the amount of water present will be =
`(0.347g)/(0.946g)* 100g=36.68g`

Hence, the mass of water present in given amount of hydrate is 36.68 grams.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of water = 36.68 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

`\text{Moles of water}=(36.38g)/(18g/mol)=2.04mol`

Hence, the number of moles of water are 2.04 moles.

Answer 2

The calculation for the amount of water present in the given amount of hydrate is shown below,
amount water = (100 g hydrate) x (0.347 g H2O / 0.946 g hydrate)
= 36.68 g
Thus, the amount of water present in the hydrate is approximately 36.68 g.