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Magnet A has twice the magnetic field strength of magnet B and pulls on magnet B with a force of 100 N. The amount of force that magnet A exerts on magnet B isA) about 50 N.B) exactly 100 N.C) more than 100 N.D) not enough information

User Ju Nogueira
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1 Answer

23 votes
23 votes

The force exerted by the magnetic in terms of the magnetic field is,


F\propto B

Where B is the magnetic fied strength and F is the force.

Thus, if the magnetic A has twice magnetic field strength than the magnet B,

Then,


B_A=2B_B

Thus, the force exerted by the magnet B is,


\begin{gathered} F_B\propto B_B \\ F_B\propto(B_A)/(2) \\ F_B=(F_A)/(2) \\ F_B=(100)/(2) \\ F_B=50\text{ N} \end{gathered}

Thus, the force exerted by the magnet B on magnet A is 50 N.

The force exerted by the magnet A exerts on the magnet B is exactly 100 N as given.

Hence, the option B is the correct answer.

User Somallg
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