Question

A golfer strikes a 0.059-kg golf ball with a force of 290 N. If the ball moves with a velocity of 69 m/s,

calculate the time the ball is in contact with the club.

Answer 1

0.014s

Step-by-step explanation:

Given parameters:

mass of golf ball = 0.059kg

force applied = 290N

velocity = 69m/s

initial velocity = 0m/s

Unknown:

Time of contact = ?

Solution;

We know that momentum is the quantity of motion of body possess;

Momentum = mass x velocity

Momentum = 0.059 x 69 = 4.1kgm/s

Also; impulse is the effect of the force acting on a body;

impulse = force x time = momentum

So;

Force x time = momentum

Time =
`(momentum)/(force )` =
`(4.1)/(290)` = 0.014s