Question

If the man has an initial velocity of 0.4 m/s with a time of 5.8 seconds and an experimental displacement of 8.167 meters and acceleration of 0.343 m/s^2, what is his calculated displacement?

Group of answer choices

7.98 m

7.62 m

8.99 m

8.09 m

Answer 1

8.09

Step-by-step explanation:

Use: s = ut + 1/2at^2

s = displacement

u = initial velocity

a = acceleration

t = time

Plug in numbers and get: 8.09