Question

what is the equation of the line that passes through the points (−1, 3) and (1, 11)? (5 points) 4x − y = 1 4x y = 1 x − 4y = −13 4x − y = −7

Answer 1

find slope
(y2-y1)/(x2-x1) is slope
(11-3)/(1-(-1))=8/2=4
y=4x+b
input a point
(1,11)
x=1
y=11
11=4(1)+b
11=4+b
minus 4 from both sides
7=b

the equatin is
y=4x+7

the closest one
minus 4x from both sides
y-4x=7
times everybody by -1
4x-y=-7

last choice is answer

Answer 2

Find gradient;
m=
`(change in y)/(change in x)`
m=
`(11-3)/(1--1)`
m=
`(8)/(2)`
m=4
Equation line;
y=4x+c
Replacing for x and y;
3=4(-1)+c
3=-4+c
c=7
y=4x+7