Question

In triangle ABC, a = 5.3 cm, b = 4.8 cm, and c = 9.2 cm.

Determine the measures of the three interior angles of triangle ABC.

PLZ HELP

Answer 1

a= 25.69, b=23.12, c=131.119

Explanation:

`cosa=(B^(2) +C^(2) -A^(2) )/(2BC) \\ =(79.59)/(88.32) \\ a = 25.69`

`cos(b)=(A^(2) +C^(2) -B^(2) )/(2AC) \\ =(89.69)/(97.52)\\ b=23.12\\c=180-23.12-25.69\\ = 131.119`