Question

The reaction A→B has been experimentally determined to be second order. The initial rate is 0.0100M/s at an initial concentration of A of 0.300M. Determine the initial rate at [A]=0.900M.

Answer 1

0.09 M/s is the initial rate when concentration of reactant A is 0.900 M.

Step-by-step explanation:

A → B

1) Initial concentration of A = [A] =0.300 M

Rate constant of the reaction , k = ?

Rate equation for the second order kinetic is given as:

`R=k[A]^2`

`0.0100M/s=k[0.300 M]^2`

`k=(0.0100M/s)/([0.300 M]^2)=0.1111 M^(-1) s^(-1)`

2) Rate of the reaction when initial concentration of A was 0.900M be R'.

[A] = 0.900M

`R'=k[A]^2`

`R'=0.1111 M^(-1) s^(-1)* [0.900 M]^2`

`R'=0.09 M/s`