Question

A 10.0 gram piece of metal is placed in an insulated calorimeter containing 250.0 g of water initially at 20.0°C. If the final temperature of the mixture is 25.0°C, what is the heat change of water?

A) 5230 J
B) −5230 J
C) 209 J
D) −209 J
E) 5440 J

Answer 1

The heat change of water is calculated through the equation,
H = m(cp)dT
where H is heat, m is mass, cp is the specific heat, and dT is the change is temperature. Substituting the known values,
H = (250 g)(4.18 J/g°C)(25°C - 20°C) = 5255 J
The nearest value to this is letter A. 5230 J.