Question

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

3N2H4(l) => 4NH3(g) + N2(g)

Given: 2.6mol N2H4

Answer 1

we are given with the equation 3N2H4(l) => 4NH3(g) + N2(g) that shows the decomposition of N2H4 to give ammonia and nitrogen gas. 3 moles of N2H4 forms 4 moles of NH3. When 2.6 moles N2H4 are used, 3.47 moles of ammonia is formed