Question

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

–5

–3

3

4

Answer 1

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?


–5

Answer 2

The correct option is 1.

Explanation:

The given quadratic equation is

`x^2+bx+5=0`

A quadratic equation
`ax^2+bx+c=0` have to real solution if the value of discriminant is garter than 0.

`b^2-4ac>0`

`b^2-4(1)(5)>0`

`b^2-20>0`

Add 20 on both the sides.

`b^2>20`

It is possible if

`b<-√(20), b>√(20)`

`b<-4.472, b>4.472`

Since -5<-.4.472, therefore option 1 is correct.