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If the margin of error in an estimate for the mean weight of a shipment is + or -2 pounds at a confidence level of 95 percent, what will be the margin of error at a confidence level of 98 percent? Be sure to show how you arrived at your answer.

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The z-value for a confidence level of 95% is 1.960, and for a confidence level of 98% is 2.326.
The MoE at a confidence level of 98% will become:

2*(2.326)/(1.960)=2.373\ pounds
User Walter Williams
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