Given :
• 0.020 moles of barium oxide participated in a chemical reaction.
,
• Molecular mass for BaO = (137.327+16 ) = 153.33g/mol
• We will the following formula:
n = mass Bao/Molecular Mass BaO
therefore Mass BaO = n*Molecular Mass
Mass = 0.020mol* 153.33g/mol
=3.0666g
• This means that the correct number of significant digits
(Mass ) =3.07 g
(extra notes: because of 0.020 has 3 significant figures , so our answer will also need to be expressed with 3 signicant figures )