Question

Is anyone available for a pre-calc question? Thanks in advance for your help

Answer 1

STEP - BY - STEP EXPLANATION

What to find?

The equivalent expression.

Given:

`cos2x-sinx`

Step 1

Simplify cos2x

`\begin{gathered} cos2x=cos(x+x)=cosxcosx-sinxsinx \\ \\ =cos^2x-sin^2x \end{gathered}`

Step 2

Replace the above in the given expression.

`cos^2x-sin^2x-sinx`

ANSWER

`cos^2x-sin^2x-sinx`